Restriction of a closed compact set in a product space to a set of coordinates #
We show that the image of a compact closed set s in a product Π i : ι, α i by
the restriction to a subset of coordinates S : Set ι is a closed set.
The idea of the proof is to use isClosedMap_snd_of_compactSpace, which is the fact that if
X is a compact topological space, then Prod.snd : X × Y → Y is a closed map.
We remark that s is included in the set Sᶜ.restrict ⁻¹' (Sᶜ.restrict '' s), and we build
a homeomorphism Sᶜ.restrict ⁻¹' (Sᶜ.restrict '' s) ≃ₜ Sᶜ.restrict '' s × Π i : S, α i.
Sᶜ.restrict '' s is a compact space since s is compact, and the lemma applies,
with X = Sᶜ.restrict '' s and Y = Π i : S, α i.
Given a set in a product space s : Set (Π j, α j) and a set of coordinates S : Set ι,
Sᶜ.restrict '' s × (Π i : S, α i) is the set of functions that coincide with an element of s
on Sᶜ and are arbitrary on S.
reorderRestrictProd sends a term of that type to Π j, α j by looking for the value at j
in one part of the product or the other depending on whether j is in S or not.
Instances For
Homeomorphism between the set of functions that concide with a given set of functions away
from a given set S, and dependent functions away from S times any value on S.
Equations
- One or more equations did not get rendered due to their size.
Instances For
The image by preimageImageRestrict α S s of s seen as a set of
Sᶜ.restrict ⁻¹' (Sᶜ.restrict '' s) is a set of Sᶜ.restrict '' s × (Π i : S, α i), and the
image of that set by Prod.snd is S.restrict '' s.
Used in IsCompact.isClosed_image_restrict to prove that the restriction of a compact closed set
in a product space to a set of coordinates is closed.
The restriction of a compact closed set in a product space to a set of coordinates is closed.