Order-connected sets are null-measurable #
This file proves that order-connected sets in ℝⁿ under the pointwise order are null-measurable.
Recall that x ≤ y iff ∀ i, x i ≤ y i, and s is order-connected iff
∀ x y ∈ s, ∀ z, x ≤ z → z ≤ y → z ∈ s.
Main declarations #
Set.OrdConnected.null_frontier: The frontier of an order-connected set inℝⁿhas measure0.
Notes #
We prove null-measurability in ℝⁿ with the ∞-metric, but this transfers directly to ℝⁿ with
the Euclidean metric because they have the same measurable sets.
Null-measurability can't be strengthened to measurability because any antichain (and in particular
any subset of the antidiagonal {(x, y) | x + y = 0}) is order-connected.
Sketch proof #
- To show an order-connected set is null-measurable, it is enough to show it has null frontier.
- Since an order-connected set is the intersection of its upper and lower closure, it's enough to show that upper and lower sets have null frontier.
- WLOG let's prove it for an upper set
s. - By the Lebesgue density theorem, it is enough to show that any frontier point
xofsis not a Lebesgue point, namely we want the density ofsover small balls centered atxto not tend to either0or1. - This is true, since by the upper setness of
swe can intercalate a ball of radiusδ / 4insintersected with the upper quadrant of the ball of radiusδcentered atx(recall that the balls are taken in the ∞-norm, so they are cubes), and another ball of radiusδ / 4insᶜand the lower quadrant of the ball of radiusδcentered atx.
TODO #
Generalize so that it also applies to ℝ × ℝ, for example.
theorem
Set.OrdConnected.null_frontier
{ι : Type u_1}
[Fintype ι]
{s : Set (ι → ℝ)}
(hs : s.OrdConnected)
:
theorem
Set.OrdConnected.nullMeasurableSet
{ι : Type u_1}
[Fintype ι]
{s : Set (ι → ℝ)}
(hs : s.OrdConnected)
:
theorem
IsAntichain.volume_eq_zero
{ι : Type u_1}
[Fintype ι]
{s : Set (ι → ℝ)}
[Nonempty ι]
(hs : IsAntichain (fun (x1 x2 : ι → ℝ) => x1 ≤ x2) s)
: