Convex cones in inner product spaces #
We define Set.innerDualCone to be the cone consisting of all points y such that for
all points x in a given set 0 ≤ ⟪ x, y ⟫.
Main statements #
We prove the following theorems:
ConvexCone.innerDualCone_of_innerDualCone_eq_self: TheinnerDualConeof theinnerDualConeof a nonempty, closed, convex cone is itself.ConvexCone.hyperplane_separation_of_nonempty_of_isClosed_of_notMem: This variant of the hyperplane separation theorem states that given a nonempty, closed, convex coneKin a complete, real inner product spaceHand a pointbdisjoint from it, there is a vectorywhich separatesbfromKin the sense that for all pointsxinK,0 ≤ ⟪x, y⟫_ℝand⟪y, b⟫_ℝ < 0. This is also a geometric interpretation of the Farkas lemma.
The dual cone #
The dual cone is the cone consisting of all points y such that for
all points x in a given set 0 ≤ ⟪ x, y ⟫.
Equations
Instances For
Dual cone of the convex cone {0} is the total space.
Dual cone of the total space is the convex cone {0}.
The inner dual cone of a singleton is given by the preimage of the positive cone under the
linear map fun y ↦ ⟪x, y⟫.
The dual cone of s equals the intersection of dual cones of the points in s.
The inner dual cone of a pointed cone is a pointed cone.
Equations
Instances For
The inner dual cone of a proper cone is a proper cone.
Instances For
This is a stronger version of the Hahn-Banach separation theorem for closed convex cones. This is also the geometric interpretation of Farkas' lemma.
Alias of ConvexCone.hyperplane_separation_of_nonempty_of_isClosed_of_notMem.
This is a stronger version of the Hahn-Banach separation theorem for closed convex cones. This is also the geometric interpretation of Farkas' lemma.
The inner dual of inner dual of a non-empty, closed convex cone is itself.
The dual of the dual of a proper cone is itself.
This is a relative version of
ConvexCone.hyperplane_separation_of_nonempty_of_isClosed_of_notMem, which we recover by setting
f to be the identity map. This is also a geometric interpretation of the Farkas' lemma
stated using proper cones.