Unit Partition #
Fix n a positive integer. BoxIntegral.unitPartition.box are boxes in ι → ℝ obtained by
dividing the unit box uniformly into boxes of side length 1 / n and translating the boxes by
vectors ν : ι → ℤ.
Let B be a BoxIntegral. A unitPartition.box is admissible for B (more precisely its index is
admissible) if it is contained in B. There are finitely many admissible unitPartition.box for
B and thus we can form the corresponding tagged prepartition, see
BoxIntegral.unitPartition.prepartition (note that each unitPartition.box comes with its
tag situated at its "upper most" vertex). If B satisfies hasIntegralVertices, that
is its vertices are in ι → ℤ, then the corresponding prepartition is actually a partition.
Main definitions and results #
BoxIntegral.hasIntegralVertices: aPropthat states that the vertices of the box have coordinates inℤBoxIntegral.unitPartition.box: aBoxIntegral, indexed byν : ι → ℤ, with verticesν i / nand of side length1 / n.BoxIntegral.unitPartition.admissibleIndex: ForB : BoxIntegral.Box, the set of indices ofunitPartition.boxthat are subsets ofB. This is a finite set.BoxIntegral.unitPartition.prepartition_isPartition: ForB : BoxIntegral.Box, ifBhas integral vertices, then the prepartition ofunitPartition.boxadmissible forBis a partition ofB.tendsto_tsum_div_pow_atTop_integral: letsbe a bounded, measurable set ofι → ℝwhose frontier has zero volume and letFbe a continuous function. Then the limit asn → ∞of∑ F x / n ^ card ι, where the sum is over the points ins ∩ n⁻¹ • (ι → ℤ), tends to the integral ofFovers.tendsto_card_div_pow_atTop_volume: letsbe a bounded, measurable set ofι → ℝwhose frontier has zero volume. Then the limit asn → ∞ofcard (s ∩ n⁻¹ • (ι → ℤ)) / n ^ card ιtends to the volume ofs.tendsto_card_div_pow_atTop_volume': a version oftendsto_card_div_pow_atTop_volumewhere we assume in addition thatx • s ⊆ y • swhenever0 < x ≤ y. Then we get the same limitcard (s ∩ x⁻¹ • (ι → ℤ)) / x ^ card ι → volume sbut the limit is over a real variablex.
A BoxIntegral.Box has integral vertices if its vertices have coordinates in ℤ.
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Any bounded set is contained in a BoxIntegral.Box with integral vertices.
A BoxIntegral, indexed by a positive integer n and ν : ι → ℤ, with corners ν i / n
and of side length 1 / n.
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The tag of (the index of) a unitPartition.box.
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- BoxIntegral.unitPartition.tag n ν i = (↑(ν i) + 1) / ↑n
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For x : ι → ℝ, its index is the index of the unique unitPartition.box to which
it belongs.
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For B : BoxIntegral.Box, the set of indices of unitPartition.box that are subsets of B.
This is a finite set. These boxes cover B if it has integral vertices, see
unitPartition.prepartition_isPartition.
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For B : BoxIntegral.Box, the TaggedPrepartition formed by the set of all
unitPartition.box whose index is B-admissible.
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- One or more equations did not get rendered due to their size.
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If B : BoxIntegral.Box has integral vertices and contains the point x, then the index of
x is admissible for B.
If B : BoxIntegral.Box has integral vertices, then prepartition n B is a partition of
B.
Let s be a bounded, measurable set of ι → ℝ whose frontier has zero volume and let F
be a continuous function. Then the limit as n → ∞ of ∑ F x / n ^ card ι, where the sum is
over the points in s ∩ n⁻¹ • (ι → ℤ), tends to the integral of F over s.
Let s be a bounded, measurable set of ι → ℝ whose frontier has zero volume. Then the limit
as n → ∞ of card (s ∩ n⁻¹ • (ι → ℤ)) / n ^ card ι tends to the volume of s. This is a
special case of tendsto_card_div_pow with F = 1.
A version of tendsto_card_div_pow_atTop_volume for a real variable.